2x^2+2y^2-3x-4y-10=0

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Solution for 2x^2+2y^2-3x-4y-10=0 equation: 


Simplifying
2x2 + 2y2 + -3x + -4y + -10 = 0

Reorder the terms:
-10 + -3x + 2x2 + -4y + 2y2 = 0

Solving
-10 + -3x + 2x2 + -4y + 2y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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